document.write( "Question 373137: The perimeter of a rectangle is 62inches, the length exceeds the width by 23inches. Find teh length and width? \n" ); document.write( "
Algebra.Com's Answer #265776 by avani(25)\"\" \"About 
You can put this solution on YOUR website!
The perimeter of a rectangle is 62inches, the length exceeds the width by 23inches. Find teh length and width?\r
\n" ); document.write( "\n" ); document.write( "perimeter of a rectangle= 2(L) + 2(W)
\n" ); document.write( "Let length (L) = x+23 inches
\n" ); document.write( "Width (W) = 23 inches
\n" ); document.write( "Perimeter of a rectangle(P) = 62inches
\n" ); document.write( "sub. in the formula
\n" ); document.write( "perimeter of a rectangle= 2(L) + 2(W)
\n" ); document.write( " 62 = 2(x+23) + 2(23)
\n" ); document.write( " 62 = 2x+46+46
\n" ); document.write( " 62=2x+92
\n" ); document.write( " 62-92=2x
\n" ); document.write( " -30/2=x
\n" ); document.write( " -15=x
\n" ); document.write( "As a result, length (L) = x+23 inches = -15+23 = 8 inches and Width (W) = 23 inches\r
\n" ); document.write( "\n" ); document.write( "Check:
\n" ); document.write( "perimeter of a rectangle= 2(L) + 2(W)=2(8)+2(23)=62 inches\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
\n" );