document.write( "Question 373080: A square photo graph of unknown dimensions (X by X) is to be place on a rectangular background that is 6 inches longer than the photo and 3 inches wider than the photo. \r
\n" ); document.write( "\n" ); document.write( "You must first determine how to now represent the length and width of the rectangular background.\r
\n" ); document.write( "\n" ); document.write( "If the area of the rectangular background is to be 340 sq. inches write an equation using A = l x w and solve the equation and tell the dimensions (X by X) of the original photograph.\r
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\n" ); document.write( "\n" ); document.write( "accurately determine an equation using A = l x w and solve the equation then, tell the dimensions (X by X) of the original photograph
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Algebra.Com's Answer #265771 by ankor@dixie-net.com(22740)\"\" \"About 
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A square photo graph of unknown dimensions (X by X) is to be place on a
\n" ); document.write( " rectangular background that is 6 inches longer than the photo and 3 inches wider than the photo.
\n" ); document.write( "You must first determine how to now represent the length and width of the rectangular background.
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\n" ); document.write( "From the given information, we can say the background dimensions are:
\n" ); document.write( "(x+6) by (x+3)
\n" ); document.write( "If the area of the rectangular background is to be 340 sq. inches write an
\n" ); document.write( " equation using A = l x w and solve the equation and tell the dimensions
\n" ); document.write( " (X by X) of the original photograph.
\n" ); document.write( ":
\n" ); document.write( "(x+6)(x+3) = 340
\n" ); document.write( "FOIL
\n" ); document.write( "x^2 + 3x + 6x + 18 = 340
\n" ); document.write( "x^2 + 9x + 18 - 340 = 0
\n" ); document.write( "x^2 + 9x - 322 = 0
\n" ); document.write( "Factors to
\n" ); document.write( "(x+23)(x-14 = 0
\n" ); document.write( "The positive solution
\n" ); document.write( "x = 14 inches, the side of the square photograph
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\n" ); document.write( "Check solution by finding the area of the background
\n" ); document.write( "(14+6) * (14+3) = 340\r
\n" ); document.write( "\n" ); document.write( "a
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