document.write( "Question 373386: Boris can jog to work in 2/3 of an hour. When he rides his bike, it takes him 1/4 of an hour. If he rides 9 miles per hour faster than he jogs, how far away is his work? \n" ); document.write( "
Algebra.Com's Answer #265767 by robertb(5830)\"\" \"About 
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Let j = jogging rate, r = riding rate.
\n" ); document.write( "Then \"2j%2F3+=+r%2F4\", or \"j+=+3r%2F8\". Also r = j + 9.
\n" ); document.write( "\"r+=+3r%2F8+%2B+9\",
\n" ); document.write( "\"5r%2F8+=+9\", or r = 14.4 miles per hour, his riding rate.
\n" ); document.write( "j = 5.4 miles per hour, his jogging rate.
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