document.write( "Question 373243: the perimeter of a rectangle is twice the sum of its width and it length. the perimeter is 40meters and its lenght is 2 meters more than twice its width. \n" ); document.write( "

Algebra.Com's Answer #265686 by JBarnum(2146) $\"\"$ $\"About$

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$\"p=2%28W%2BL%29\"$
\n" ); document.write( " $\"P=40\"$
\n" ); document.write( " $\"L=2%2BW\"$
\n" ); document.write( "

\n" ); document.write( " $\"40=2%28W%2B%282%2BW%29%29\"$ divide by 2
\n" ); document.write( " $\"20=2W%2B2\"$ subtract 2
\n" ); document.write( " $\"18=2W\"$ divide by 2
\n" ); document.write( " $\"9=W\"$
\n" ); document.write( "

\n" ); document.write( " $\"L=2%2BW\"$ substitute W for 9
\n" ); document.write( " $\"L=11\"$ \n" ); document.write( "

\n" );