document.write( "Question 373138: log(x^2+9)-log(x+3)=2+log(x-3)
\n" ); document.write( "Help please! \n" ); document.write( "
Algebra.Com's Answer #265655 by CharlesG2(834)\"\" \"About 
You can put this solution on YOUR website!
log(x^2+9)-log(x+3)=2+log(x-3)
\n" ); document.write( "Help please!\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "log(x^2 + 9) - log(x + 3) = 2 + log(x - 3)
\n" ); document.write( "logarithmic rule: logb(m) - logb(n) = logb(m/n)
\n" ); document.write( "logarithmic rule: logb(m) + logb(n) = logb(mn)
\n" ); document.write( "2 = log 100
\n" ); document.write( "log((x^2 + 9)/(x + 3)) = log 100 + log(x - 3)
\n" ); document.write( "log((x^2 + 9)/(x + 3)) = log 100(x - 3)
\n" ); document.write( "log((x^2 + 9)/(x + 3)) = log 100(x - 3)
\n" ); document.write( "(x^2 + 9)/(x + 3) = 100(x - 3) (what is in parenthesis must equal)
\n" ); document.write( "x^2 + 9 = 100(x - 3)(x + 3)
\n" ); document.write( "x^2 + 9 = 100(x^2 - 9)
\n" ); document.write( "x^2 + 9 = 100x^2 - 900
\n" ); document.write( "-99x^2 = -909
\n" ); document.write( "99x^2 = 909
\n" ); document.write( "x^2 = 909/99 = 101/11
\n" ); document.write( "x = +- sqrt(101/11)
\n" ); document.write( "can not take log of a negative number, so x = -sqrt(101/11) does not work
\n" ); document.write( "so x = sqrt(101/11)\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
\n" );