document.write( "Question 373122: I don't even know where to start. The problem is log2^x = 1/3log2^27. Can you please show me step by step. \n" ); document.write( "
Algebra.Com's Answer #265649 by CharlesG2(834)\"\" \"About 
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I don't even know where to start. The problem is log2^x = 1/3log2^27. Can you please show me step by step.\r
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\n" ); document.write( "\n" ); document.write( "log 2^x = (1/3)log 2^27
\n" ); document.write( "logarithmic rule: nlogb(m) = logb(m^n)
\n" ); document.write( "log 2^x = log 2^(27 * 1/3)
\n" ); document.write( "log 2^x = log 2^9
\n" ); document.write( "2^x = 2^9 (these must equal)
\n" ); document.write( "x = 9
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