document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=373086>Question 373086</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find an equation of the line passing through the pair of points. write equation in the form of Ax+Bx=C\r<BR>\n" );
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document.write( "(0,0) (-1/8, 1/3) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #265638 by </B><A HREF=/tutors/aboutme.mpl?userid=amoresroy><B>amoresroy(361)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=amoresroy><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=amoresroy><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=265638\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> find an equation of the line passing through the pair of points. write equation in the form of Ax+Bx=C \r<BR>\n" );
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document.write( "(0,0) (-1/8, 1/3)\r<BR>\n" );
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document.write( "(y-0)/(x-0) = [(y-1/3)/(x--1/8)]<BR>\n" );
document.write( "         y/x= (y-1/3)/(x+1/8)<BR>\n" );
document.write( "  (y-1/3)/y = (x+1/8)/x\r<BR>\n" );
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document.write( "  1 -1/3y    = 1 +1/8x<BR>\n" );
document.write( "    -1/3y    = 1/8x<BR>\n" );
document.write( "Cross multiply<BR>\n" );
document.write( "-8x = 3y<BR>\n" );
document.write( "8x + 3y = 0   \r<BR>\n" );
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document.write( " </SPAN>\n" );
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