document.write( "Question 372992: Jane invested $50,000 into two accounts. The first paid 7% interest and the second paid 12% interest. If she earned $4350 the first year, how much money did she invest in each account? \n" ); document.write( "
Algebra.Com's Answer #265589 by robertb(5830)![]() ![]() You can put this solution on YOUR website! 0.07x + 0.12(50,000 - x) = 4350, \n" ); document.write( "0.07x + 6000-0.12x = 4350, \n" ); document.write( "-0.05x = -1650, \n" ); document.write( "x = 33,000, the amount of investment at 7%, \n" ); document.write( "50,000 - x = 17,000, the amount of investment at 12%. \n" ); document.write( " |