document.write( "Question 79731: You invested $10,000 in two stocks paying 9% and 12% annual interest,
\n" ); document.write( "respectively. At the end of the year, the total interest from these investments
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Algebra.Com's Answer #265579 by DarkOnyx(1)\"\" \"About 
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Let x= the amount invested at 9%
\n" ); document.write( "Let 10000-x = the amount invested at 12%\r
\n" ); document.write( "\n" ); document.write( "0.09x+ 0.12(10000-x)=930
\n" ); document.write( "0.09x+1200-0.12x=930
\n" ); document.write( "-0.03x=--270
\n" ); document.write( "x=9000\r
\n" ); document.write( "\n" ); document.write( "9000 is the amount invested at 9%\r
\n" ); document.write( "\n" ); document.write( "Check:
\n" ); document.write( "0.09(9000)+0.12(10000-9000)=930
\n" ); document.write( "810+120=930
\n" ); document.write( "930=930 \r
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