document.write( "Question 372800: The number of miles, M, that a car can travel on a gallon of gas during a trip depends on the average speed, v, of the car on the trip according to the model M = -.011v^2 + 1.3v. Find the average speed that will minimize the costs for a trip. A person wants to take a 1900 mile trip in the car and wants to spend less than $55 for gas. If gas costs $1.10, how fast can the person drive? \n" ); document.write( "
Algebra.Com's Answer #265578 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! The number of miles, M, that a car can travel on a gallon of gas during a trip \n" ); document.write( " depends on the average speed, v, of the car on the trip according to the model \n" ); document.write( " M = -.011v^2 + 1.3v. \n" ); document.write( " Find the average speed that will minimize the costs for a trip. \n" ); document.write( ": \n" ); document.write( "Minimum cost will be at Maximum mpg, which occurs at the axis of symmetry. \n" ); document.write( "Find the axis of symmetry of the equation M = -.011v^2 + 1.3v \n" ); document.write( "v = \n" ); document.write( "v = \n" ); document.write( "v = +59.1 mph gives max mpg (M) \n" ); document.write( "; \n" ); document.write( "; \n" ); document.write( " A person wants to take a 1900 mile trip in the car and wants to spend less than $55 for gas. \n" ); document.write( " If gas costs $1.10, how fast can the person drive? \n" ); document.write( ": \n" ); document.write( "Solve for M \n" ); document.write( "1.10(1900/M) < $55 \n" ); document.write( "Divide both sides by 1.10, results \n" ); document.write( " \n" ); document.write( "M > \n" ); document.write( "M > 38 mpg (More than 38 mpg to spend under $55) \n" ); document.write( ":\r \n" ); document.write( "\n" ); document.write( "Find the speed (v) which gives > 38 mpg. Let's use 38.1 mph \n" ); document.write( "-.011v^2 + 1.3v = 38.1 \n" ); document.write( "-.011v^2 + 1.3v - 38.1 = 0 \n" ); document.write( "Solve this using the quadratic formula, a=-.011; b=1.3; c=-38.1 \n" ); document.write( " \n" ); document.write( "do the math, you will get two solutions of \n" ); document.write( "53.8 mph and 64.4 mph \n" ); document.write( "Perhaps we can say if he drives between these two speeds he will spend <$55 \n" ); document.write( " |