document.write( "Question 372800: The number of miles, M, that a car can travel on a gallon of gas during a trip depends on the average speed, v, of the car on the trip according to the model M = -.011v^2 + 1.3v. Find the average speed that will minimize the costs for a trip. A person wants to take a 1900 mile trip in the car and wants to spend less than $55 for gas. If gas costs $1.10, how fast can the person drive? \n" ); document.write( "
Algebra.Com's Answer #265578 by ankor@dixie-net.com(22740)\"\" \"About 
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The number of miles, M, that a car can travel on a gallon of gas during a trip
\n" ); document.write( " depends on the average speed, v, of the car on the trip according to the model
\n" ); document.write( " M = -.011v^2 + 1.3v.
\n" ); document.write( " Find the average speed that will minimize the costs for a trip.
\n" ); document.write( ":
\n" ); document.write( "Minimum cost will be at Maximum mpg, which occurs at the axis of symmetry.
\n" ); document.write( "Find the axis of symmetry of the equation M = -.011v^2 + 1.3v
\n" ); document.write( "v = \"%28-1.3%29%2F%282%2A-.011%29\"
\n" ); document.write( "v = \"%28-1.3%29%2F%28-.022%29\"
\n" ); document.write( "v = +59.1 mph gives max mpg (M)
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\n" ); document.write( " A person wants to take a 1900 mile trip in the car and wants to spend less than $55 for gas.
\n" ); document.write( " If gas costs $1.10, how fast can the person drive?
\n" ); document.write( ":
\n" ); document.write( "Solve for M
\n" ); document.write( "1.10(1900/M) < $55
\n" ); document.write( "Divide both sides by 1.10, results
\n" ); document.write( "\"1900%2FM\" < 50
\n" ); document.write( "M > \"1900%2F50\"
\n" ); document.write( "M > 38 mpg (More than 38 mpg to spend under $55)
\n" ); document.write( ":\r
\n" ); document.write( "\n" ); document.write( "Find the speed (v) which gives > 38 mpg. Let's use 38.1 mph
\n" ); document.write( "-.011v^2 + 1.3v = 38.1
\n" ); document.write( "-.011v^2 + 1.3v - 38.1 = 0
\n" ); document.write( "Solve this using the quadratic formula, a=-.011; b=1.3; c=-38.1
\n" ); document.write( "\"v+=+%28-1.3+%2B-+sqrt%281.3%5E2-4%2A-.011%2A-38.1+%29%29%2F%282%2A-.011%29+\"
\n" ); document.write( "do the math, you will get two solutions of
\n" ); document.write( "53.8 mph and 64.4 mph
\n" ); document.write( "Perhaps we can say if he drives between these two speeds he will spend <$55
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