document.write( "Question 372808: Diohantius lived X years. He spent 1/6 of his life in boyhood, and 1/12 of his life as a youth. After 1/7 more of his life passed, he became married. 5 years later, he had a son. The son lived 1/2 as long as Dipohantus, and died 4 years before Diophantus died. How old was Diophantus? \n" ); document.write( "
Algebra.Com's Answer #265573 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Diohantius lived X years. He spent 1/6 of his life in boyhood, and 1/12 of his life as a youth. \n" ); document.write( " After 1/7 more of his life passed, he became married. 5 years later, he had a son. \n" ); document.write( " The son lived 1/2 as long as Dipohantus, and died 4 years before Diophantus died. \n" ); document.write( " How old was Diophantus? \n" ); document.write( ": \n" ); document.write( "Let x = his final age \n" ); document.write( ": \n" ); document.write( "a lengthy but simple equation \n" ); document.write( "Final age = child + youth + bach + marriage + son's age + 4 \n" ); document.write( "x = \n" ); document.write( ": \n" ); document.write( "Common denominator of 12*7 = 84 \n" ); document.write( "x = \n" ); document.write( ": \n" ); document.write( "x = \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "x = 84 is his final age \n" ); document.write( ": \n" ); document.write( "Check: \n" ); document.write( "14 + 7 + 12 + 5 + 42 + 4 = 84 \n" ); document.write( " |