document.write( "Question 372868: Hi, I'm having trouble completing the square to find the standard form of the following equation.(I've only ever done this with one variable so not sure how to proceed)\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2-9y2%2B36y-72=0\"\r
\n" ); document.write( "\n" ); document.write( "Could you please let me know the steps I have to take to complete the square with two variables? Thanks for your time :)
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Algebra.Com's Answer #265548 by robertb(5830)\"\" \"About 
You can put this solution on YOUR website!
\"x%5E2+-+9%28y%5E2-4y%29+-+72+=+0\",
\n" ); document.write( "\"x%5E2+-9%28y%5E2-4y+%2B+4%29+%2B+36+-+72+=+0\",
\n" ); document.write( "\"x%5E2+-+9%28y-2%29%5E2+-+36+=+0\",
\n" ); document.write( "\"x%5E2+-+9%28y-2%29%5E2+=+36\",
\n" ); document.write( "\"x%5E2%2F36+-+%28y-2%29%5E2%2F4+=+1\",
\n" ); document.write( "it's an hyperbola with vertex at (0,2), y-axis as the conjugate axis and y = 2 as the transverse axis.
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