document.write( "Question 372702: A candy store sells boxes of candy containing caramels and cremes. Each box sells for $12.50 and holds 30 pieces of candy (all pieces are the same size). If the caramels cost $0.25 to produce and the cremes cost $0.45, how many of each should be in a box to make a profit of $3? \n" ); document.write( "
Algebra.Com's Answer #265539 by ankor@dixie-net.com(22740)\"\" \"About 
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A candy store sells boxes of candy containing caramels and cremes.
\n" ); document.write( " Each box sells for $12.50 and holds 30 pieces of candy (all pieces are the same size).
\n" ); document.write( "If the caramels cost $0.25 to produce and the cremes cost $0.45,
\n" ); document.write( " how many of each should be in a box to make a profit of $3?
\n" ); document.write( ":
\n" ); document.write( "Let c = no. of caramels
\n" ); document.write( "Let m = no. of cremes
\n" ); document.write( ":
\n" ); document.write( "Total candy equation
\n" ); document.write( "c + m = 30
\n" ); document.write( "c = (30-m); this form for substitution
\n" ); document.write( ":
\n" ); document.write( "Cost equation
\n" ); document.write( ".25c + .45m = 12.50 - 3.00
\n" ); document.write( ".25c + .45m = 9.50
\n" ); document.write( "Substitute (30-m) for c
\n" ); document.write( ".25(30-m) + .45m = 9.50
\n" ); document.write( "7.50 - .25m + .45m = 9.50
\n" ); document.write( "-.25m + .45m = 9.50 -7.50
\n" ); document.write( ".20m = 2.00
\n" ); document.write( "m = \"2.00%2F.20\"
\n" ); document.write( "m = 10 creams in each box
\n" ); document.write( "then
\n" ); document.write( "20 - 10 = 20 caramels in each box
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "you can check our solutions by substitution in the original equation \n" ); document.write( "
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