document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=41059>Question 41059</A>: <I><SPAN STYLE=\"word-break: break-all;\"> SOLVE FOR X PLEASE<BR>\n" );
document.write( "AX+BY=M<BR>\n" );
document.write( "BX+AY=C<BR>\n" );
document.write( "THANK YOU </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #26553 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=26553\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> To solve for x, let's use the linear combination method to eliminate y...so from<BR>\n" );
document.write( "AX+BY=M<BR>\n" );
document.write( "BX+AY=C<BR>\n" );
document.write( "we get<BR>\n" );
document.write( "A^2X + ABY = AM<BR>\n" );
document.write( "B^2X + ABY = BC<BR>\n" );
document.write( "now subtract them to get<BR>\n" );
document.write( "A^2X - B^2X = AM - BC<BR>\n" );
document.write( "factor and divide out and get<BR>\n" );
document.write( "X(A^2 - B^2) = AM - BC<BR>\n" );
document.write( "X = (AM - BC) / (A^2 - B^2) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );