document.write( "Question 372797: Jack wanted to throw an apple to Lauren, who was on a balcony 40 feet above him, so he tossed it upward with an initial speed of 56 ft/s. Lauren missed it on the way up, but then caught it on the way down. How long was the apple in the air?\r
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document.write( "Would I use the equation h(t) = -16t^2 + 56t +40? (where h = height and t = time) I'm not very good at solving quadratic word problems :( \n" );
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Algebra.Com's Answer #265524 by nerdybill(7384)![]() ![]() You can put this solution on YOUR website! Well, you're close \n" ); document.write( "The general equation is \n" ); document.write( "h(t) = -(1/2)gt^2 + Vot + h(0) \n" ); document.write( "where \n" ); document.write( "g is gravity 32 ft/sec^2 \n" ); document.write( "Vo is initial velocity \n" ); document.write( "h(0) is initial height of Jack (not Lauren) \n" ); document.write( ". \n" ); document.write( "So, plugging in what we know \n" ); document.write( "h(t) = -(1/2)(32)t^2 + 56t + 0 \n" ); document.write( "which reduces to \n" ); document.write( "h(t) = -16t^2 + 56t \n" ); document.write( ". \n" ); document.write( "So, since Lauren is 40 feet up -- set h(t) to 40 and solve for t: \n" ); document.write( "h(t) = -16t^2 + 56t \n" ); document.write( "40 = -16t^2 + 56t \n" ); document.write( "0 = -16t^2 + 56t - 40 \n" ); document.write( "multiply both sides by -1: \n" ); document.write( "0 = 16t^2 - 56t + 40 \n" ); document.write( "divide both sides by 8: \n" ); document.write( "0 = 2t^2 - 7t + 5 \n" ); document.write( "0 = (2t-5)(t-1) \n" ); document.write( "So, \n" ); document.write( "t = {1, 5/2} \n" ); document.write( "1 sec represents the time the apple reaches 40 ft (going up) \n" ); document.write( "So \n" ); document.write( "5/2 secs or \n" ); document.write( "2 and 1/2 secs (is your solution)\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |