document.write( "Question 372724: Find the center of a circle defined by the equation : x^2+y^2+12x+8y+16=0. \n" ); document.write( "
Algebra.Com's Answer #265453 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
Complete the square in \"x\" and \"y\".
\n" ); document.write( "\"x%5E2%2By%5E2%2B12x%2B8y%2B16=0\"
\n" ); document.write( "\"%28x%5E2%2B12x%2B36%29%2B%28y%5E2%2B8y%2B16%29%2B16=36%2B16\"
\n" ); document.write( "\"%28x%2B6%29%5E2%2B%28y%2B4%29%5E2=36\"
\n" ); document.write( "Compare to the general equation for a circle centered at (\"h\",\"k\") with a radius \"R\":
\n" ); document.write( "\"%28x-h%29%5E2%2B%28y-k%29%5E2=R%5E2\"
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