document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=41088>Question 41088</A>: <I><SPAN STYLE=\"word-break: break-all;\"> LINK HAS 42 COINS CONSISTING OF NICKELS AND DIMES. IF THE TOTAL VALUE IS $3.30, FIND THE NUMBER OF EACH COIN.THANKS IM LEARING </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #26545 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=26545\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let n be the number of nickels, and then d will be the number of dimes.  Their values will then be 5n and 10d respectively...then we have<BR>\n" );
document.write( "5n + 10d = 330 (thinking in cents now)<BR>\n" );
document.write( "n + d = 42<BR>\n" );
document.write( "If we multiply the bottom one by 5 and subtract, <BR>\n" );
document.write( "5n + 10d = 330<BR>\n" );
document.write( "-(5n + 5d = 210)<BR>\n" );
document.write( "we get<BR>\n" );
document.write( "5d = 120<BR>\n" );
document.write( "d = 24 and<BR>\n" );
document.write( "n = 18<BR>\n" );
document.write( "Check to see they add to $3.30... </SPAN>\n" );
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