document.write( "Question 372692: in the past year, 13%of businesses have eleminated jobs. if five businesses are randomly selected, find the probability that at least three eliminated jobs during the year. \n" ); document.write( "

Algebra.Com's Answer #265448 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi,
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document.write( "Note: The probability of x successes in n trials is: 
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document.write( "P = nCx*  where p and q are the probabilities of success and failure respectively. 
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document.write( "In this case p = .13 , q = .87  and n = 5 
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document.write( "nCx = 
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document.write( "P(at least 3 of the five eliminated jobs) = 1 - P(0) -P(1) -P(2)
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document.write( "P(0) = .4984  (.87)^5
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document.write( "P(1) = .3724  5*(.13)^1(.87)^4
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document.write( "P(2) = .1113  10*(.13)^2(.87)^3\r
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document.write( "P(at least 3 of the five eliminated jobs) = 1 - .9821 = .0179 \n" );
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