document.write( "Question 372700: A man flies an airplane from Fargo to Bismark -- a distance of 180 mi. Because he is flying into a head wind, the trip takes 2 hours. On the way back, the wind is blowing the same speed, so it takes an 1 hour and 48 mins. What is his speed in still air and how fast is the wind blowing? \n" ); document.write( "
Algebra.Com's Answer #265439 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! A man flies an airplane from Fargo to Bismark -- a distance of 180 mi. Because he is flying into a head wind, the trip takes 2 hours. On the way back, the wind is blowing the same speed, so it takes an 1 hour and 48 mins. What is his speed in still air and how fast is the wind blowing? \n" ); document.write( "--------------- \n" ); document.write( "Upwind, the groundspeed = 180/2 = 90 mph \n" ); document.write( "Downwind, = 180/1.8 = 100 mph \n" ); document.write( "The \"speed in still air\" is the airspeed, and it's the average = 95 mph \n" ); document.write( "The windspeed is the difference = 5 mph \n" ); document.write( " \n" ); document.write( " |