document.write( "Question 372701: find the radius of the circle defined by the equation: x^2+y^2+12x+4y+76=0. \n" ); document.write( "

Algebra.Com's Answer #265431 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi,
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document.write( "The standard equation of a circle with center C(h,k) and radius r is :
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document.write( "Find the radius  
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document.write( "x^2+y^2+12x+4y+76=0
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document.write( "completing the squares
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document.write( "x^2+12x +   y^2+4y       + 76=0
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document.write( "(x+6)^2 + (y+2)^2 -36 -4 + 76 = 0
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document.write( "(x+6)^2 + (y+2)^2 = 36 = 6^2
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document.write( "radius = 6, center (-6,-2)
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