document.write( "Question 372701: find the radius of the circle defined by the equation: x^2+y^2+12x+4y+76=0. \n" ); document.write( "

Algebra.Com's Answer #265430 by Fombitz(32388) $\"\"$ $\"About$

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Complete the square in $\"x\"$ and $\"y\"$ .
\n" ); document.write( " $\"x%5E2%2By%5E2%2B12x%2B4y%2B76=0\"$
\n" ); document.write( " $\"%28x%5E2%2B12x%2B36%29%2B%28y%5E2%2B4y%2B4%29%2B76=36%2B4\"$
\n" ); document.write( " $\"%28x%2B6%29%5E2%2B%28y%2B2%29%5E2=40-76\"$
\n" ); document.write( " $\"%28x%2B6%29%5E2%2B%28y%2B2%29%5E2=-36\"$
\n" ); document.write( "Compare this equation to the general equation of a circle centered at (h,k) with a radius R.
\n" ); document.write( " $\"%28x-h%29%5E2%2B%28y-k%29%5E2=R%5E2\"$
\n" ); document.write( "In this case, your equation is not the equation for a circle.\r
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