document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=372684>Question 372684</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If an object is projected vertically upward from an altitude of s(o) feet with an intial velocity of v(o) ft/sec, then its distance above the ground after t seconds is: s(t)=-16t^2+ v(o)t+ s(o). <BR>\n" );
document.write( "If s(1)= 64 and s(2)=66, what are s(o) and v(o)?\r<BR>\n" );
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document.write( "I honestly do not know how to set the problem up! Please help, it would be greatly appreciated!Thanks :)<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #265418 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=265418\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Given:<BR>\n" );
document.write( "s(t)=-16t^2+ v(o)t+ s(o). <BR>\n" );
document.write( "If s(1)= 64 and s(2)=66, what are s(o) and v(o)?<BR>\n" );
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document.write( "So, <BR>\n" );
document.write( "when x=1 then s(1)=64<BR>\n" );
document.write( "and<BR>\n" );
document.write( "when x=2 then s(2)=66<BR>\n" );
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document.write( "From here, you now have two unknowns and two equations:<BR>\n" );
document.write( "when x=1 then s(1)=64<BR>\n" );
document.write( "s(t)=-16t^2+ v(o)t+ s(o)<BR>\n" );
document.write( "s(1)=-16(1)^2+ v(o)(1)+ s(o)<BR>\n" );
document.write( "64=-16+ v(o)+ s(o)<BR>\n" );
document.write( "89=v(o)+ s(o)  equation 1<BR>\n" );
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document.write( "when x=2 then s(2)=66<BR>\n" );
document.write( "s(t)=-16t^2+ v(o)t+ s(o)<BR>\n" );
document.write( "s(2)=-16(2)^2+ v(o)(2)+ s(o)<BR>\n" );
document.write( "66=-16(4)+ 2v(o)+ s(o)<BR>\n" );
document.write( "130=2v(o)+ s(o)  equation 2<BR>\n" );
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document.write( "Considering the \"system of equations\" then:<BR>\n" );
document.write( "130=2v(o)+ s(o)<BR>\n" );
document.write( "89=v(o)+ s(o)<BR>\n" );
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document.write( "Multiply both sides of the bottom equation by -1 and add:<BR>\n" );
document.write( "130=2v(o)+ s(o)<BR>\n" );
document.write( "-89=-v(o)- s(o)<BR>\n" );
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document.write( "41 ft/sec = v(0)<BR>\n" );
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document.write( "Substitute the above into:<BR>\n" );
document.write( "89=v(o)+ s(o)<BR>\n" );
document.write( "89=41+ s(o)<BR>\n" );
document.write( "48 feet = s(o) </SPAN>\n" );
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