document.write( "Question 372682: find the center of the circle defined by the equation 2x^2+2y^2+24x+28y+138=0.
\n" ); document.write( "I'm kinda confused on how to start solving this problem, please help. \n" ); document.write( "

Algebra.Com's Answer #265412 by Fombitz(32388) $\"\"$ $\"About$

You can put this solution on YOUR website!
Complete the square in $\"x\"$ and $\"y\"$ .
\n" ); document.write( " $\"2x%5E2%2B2y%5E2%2B24x%2B28y%2B138=0\"$
\n" ); document.write( " $\"x%5E2%2B12x%2By%5E2%2B14y%2B69=0\"$
\n" ); document.write( " $\"%28x%5E2%2B12x%2B36%29%2B%28y%5E2%2B14y%2B49%29%2B69=36%2B49\"$
\n" ); document.write( " $\"%28x%2B6%29%5E2%2B%28y%2B7%29%5E2=85-69\"$
\n" ); document.write( " $\"highlight%28%28x%2B6%29%5E2%2B%28y%2B7%29%5E2=16%29\"$
\n" ); document.write( "Compare to the general equation for a circle centered at ( $\"h\"$ , $\"k\"$ ) with a radius $\"R\"$ :
\n" ); document.write( " $\"%28x-h%29%5E2%2B%28y-k%29%5E2=R%5E2\"$
\n" ); document.write( " \n" ); document.write( "

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