document.write( "Question 372624: Find the radius of the circle defined by the equation x^2+y^2+12x+8y+16=0
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Algebra.Com's Answer #265398 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi,
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document.write( "The standard equation of a circle with center C(h,k) and radius r is :
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document.write( "Find the radius
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document.write( "completing the squares
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document.write( "x^2+y^2+12x+8y+16=0
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document.write( "(x+6)^2 + (y+4)^2 -36 -16 +16 = 0
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document.write( "(x+6)^2 + (y+4)^2 = 36 = 6^2
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document.write( "radius is 6, the center of the circle (-6,-4)\r
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