document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=372553>Question 372553</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Sylvia walked to Cathy's house at 2km/h, and then rode a bicycle back to her own house at 10km/h.  The entire trip took 3 hours.  How long a time did Sylvia walk? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #265385 by </B><A HREF=/tutors/aboutme.mpl?userid=ayalyaniv><B>ayalyaniv(6)</B></A><img src=\"/images/stars/stars-05.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ayalyaniv><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=265385\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Since this is a distance problem, you would use the rt=d equation.<BR>\n" );
document.write( "2(t)=d<BR>\n" );
document.write( "10(3-t)=d<BR>\n" );
document.write( "You are not given the distance between Sylvia's and Cathy's houses, but since it is a two-way trip, you know that both equations cover the same distance.<BR>\n" );
document.write( "So you can write 2(t)=10(3-t)<BR>\n" );
document.write( "Multiply out 2t=30-10t<BR>\n" );
document.write( "Transposing you get 12t=30.<BR>\n" );
document.write( "Dividing by 12 you get t=2.5<BR>\n" );
document.write( "Sylvia walked for 2.5 hours (and rode for half an hour)<BR>\n" );
document.write( " </SPAN>\n" );
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