document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=41089>Question 41089</A>: <I><SPAN STYLE=\"word-break: break-all;\"> FIVE liters of a 4% solution must be mixed with a 10% sloution to get a 6%solution. how many liters of the 10% are needed? thanks  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #26535 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=26535\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x be the number of liters of 10% solution.  The setup looks like this:<BR>\n" );
document.write( "5(.04) + x(.10) = (5+x)(.06)<BR>\n" );
document.write( ".2 + .1x = .3 + .06x<BR>\n" );
document.write( ".04x = .1<BR>\n" );
document.write( "x = 2.5 liters </SPAN>\n" );
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