document.write( "Question 372518: Find two consecutive odd integers such that twice the larger is 17 more than the smaller. \n" ); document.write( "
Algebra.Com's Answer #265319 by mananth(16946)![]() ![]() You can put this solution on YOUR website! let the odd integers be x & x+2 \n" ); document.write( ".. \n" ); document.write( "twice the larger = 2(x+2) \n" ); document.write( "17 more than the smaller \n" ); document.write( "= x+17 \n" ); document.write( ".. \n" ); document.write( "2(x+2) = x+17 \n" ); document.write( "2x+4 =x+17 \n" ); document.write( "2x-x= 17-4 \n" ); document.write( "x= 13 \n" ); document.write( "13, 15 are the integers \n" ); document.write( ".. \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " |