document.write( "Question 372443: Two positive numbers have a difference of 2. Their reciprocals have a sum of 20/21. What are the numbers? \n" ); document.write( "
Algebra.Com's Answer #265292 by mananth(16946)\"\" \"About 
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let the numbers be x
\n" ); document.write( "the other number will be x+2
\n" ); document.write( "1/x + 1/(x+2) = 20/21
\n" ); document.write( "((x+2)+x)/x(x+2)= 20/21
\n" ); document.write( "(2x+2)/(x(x+2)= 20/21
\n" ); document.write( "21(2x+2)= 20x(x+2)
\n" ); document.write( "42x+42=20x^2+40x
\n" ); document.write( "20x^2-2x-42=0
\n" ); document.write( "/2
\n" ); document.write( "10x^2-x-21=0
\n" ); document.write( "10x^2-15x+14x-21=0
\n" ); document.write( "10x(x-1.5)+14(x-1.5)=0
\n" ); document.write( "(10x+14)(x-1.5)=0
\n" ); document.write( "10(x+1.4)(x-1.5)=0
\n" ); document.write( "(x+1.4)(x-1.5)=0
\n" ); document.write( "x =-1.4
\n" ); document.write( "OR
\n" ); document.write( "x=1.5
\n" ); document.write( "..
\n" ); document.write( "1.5 & 3.5
\n" ); document.write( "OR
\n" ); document.write( "-1.4 & 0.6
\n" ); document.write( "...
\n" ); document.write( "m.ananth@hotmail.ca
\n" ); document.write( "
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