document.write( "Question 372455: A 5 inch by 8 inch rectangular picture has a frame of uniform width. if the area of the frame is 114 square inches, what is the width of the frame? \n" ); document.write( "
Algebra.Com's Answer #265270 by mananth(16946)\"\" \"About 
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Picture width = 5 in
\n" ); document.write( "picture length = 8 in
\n" ); document.write( "Area = 40 in^2
\n" ); document.write( "...
\n" ); document.write( "uniform width let it be x in
\n" ); document.write( "..
\n" ); document.write( "total width = 5+2x
\n" ); document.write( "total length = 8+2x
\n" ); document.write( "..
\n" ); document.write( "Total area = (5+2x)(8+2x)
\n" ); document.write( "=40+10x+16x+4x^2
\n" ); document.write( "=4x^2+26x+40
\n" ); document.write( "...
\n" ); document.write( "Total area - picture area = area of frame
\n" ); document.write( "4x^2+26x+40 -40=114\r
\n" ); document.write( "\n" ); document.write( "4x^2+26x-154=0
\n" ); document.write( "...
\n" ); document.write( "use the quadratic formula to get the roots of the equation
\n" ); document.write( "discriminant = 3140
\n" ); document.write( "x1= \"%28%28%28-26%2Bsqrt%283140%29%29%2F%288%29%29%29\"
\n" ); document.write( "x1= 3.75
\n" ); document.write( "x2=\"%28%28%28-26-sqrt%283140%29%29%2F%288%29%29%29\"
\n" ); document.write( "x2=-10.25 ( ignore )
\n" ); document.write( "width = 3.75 in
\n" ); document.write( "..
\n" ); document.write( "m.ananth@hotmail.ca
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