document.write( "Question 372296: a freight train leaves tamaqua, traveling east at 35km/hr. One hour later a passenger train leaves Tamaqua,also traveling east on a parallel track at 40km/hr. How far from tamaqua will the passenger train catch the freight train ? \n" ); document.write( "
Algebra.Com's Answer #265208 by stanbon(75887)\"\" \"About 
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a freight train leaves tamaqua, traveling east at 35km/hr. One hour later a passenger train leaves Tamaqua,also traveling east on a parallel track at 40km/hr. How far from tamaqua will the passenger train catch the freight train ?
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\n" ); document.write( "Freight Train DATA:
\n" ); document.write( "rate = 35 km/h ; time = x hrs ; distance = 35x km
\n" ); document.write( "--------------------------
\n" ); document.write( "Passenger Train DATA:
\n" ); document.write( "rate = 40 km/h ; time = x-1 hrs ; distance = 40(x-1) km
\n" ); document.write( "-----
\n" ); document.write( "Equation:
\n" ); document.write( "distance = distance
\n" ); document.write( "35x = 40x-40
\n" ); document.write( "-5x = -40
\n" ); document.write( "x = 8 hrs.
\n" ); document.write( "----
\n" ); document.write( "Distance from Tamaqua: 8*35 = 280 km
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H. \n" ); document.write( "
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