document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=371967>Question 371967</A>: <I><SPAN STYLE=\"word-break: break-all;\"> solving applications involving variation\r<BR>\n" );
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document.write( "simple interest. The simple interest I on an account varies jointly as the time t and the principal P. After one quarter (3 months) an $8000 principal earned $100 in interest. HOw much would a $10000 principal earn in 5 months?\r<BR>\n" );
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document.write( "Help, been working on this one problem for over an hour. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #265137 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=265137\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I = k * t * P ___ the constant of proportionality would probably be the monthly interest rate\r<BR>\n" );
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document.write( "100 = k * 3 * 8000 ___ k = 1 / 240\r<BR>\n" );
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document.write( "I = (1/240) * 5 * 10000 </SPAN>\n" );
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