document.write( "Question 372110: One bacterial culture is 18 days older than a second bacterial culture. In 10 days the first culture will be twice the age of the second. What is the present age of both cultures?\r
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document.write( "I know that:\r
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document.write( "The age of the bacterial culture in ten days = 2 times age of the second bacterial culture\r
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document.write( "But I don't know where to go from here. \n" );
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Algebra.Com's Answer #265107 by Greenfinch(383)![]() ![]() You can put this solution on YOUR website! younger one is x days old, older one is x + 18 days old \n" ); document.write( "In ten days 2(x + 10) = x + 28 \n" ); document.write( "Or 2x + 20 = x + 28 \n" ); document.write( "x = 8 \n" ); document.write( "Check : now 8 days and 26 days old \n" ); document.write( "in 10 days younger one is 18 days and older one is 36 days old \n" ); document.write( " |