document.write( "Question 372148: A SQUARE POSTER HAS SIDES MEASURING 2 FEET LESS THAN THE SIDES OF A SQUARE SIGN. IF THE DIFFERENCE BETWEEN THEIR AREAS IS 20 SQUARE FEET, FIND LENGTHS OF THE SIDES OF THE POSTER AND THE SIGN. \n" ); document.write( "

Algebra.Com's Answer #265088 by solver91311(24713) $\"\"$ $\"About$

You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "Typing in all caps is the electronic communications equivalent of shouting. It is both annoying and rude.\r
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\n" ); document.write( "\n" ); document.write( "Let

represent the measure of the side of the larger square. Then

is the measure of the side of the smaller square,

is the area of the smaller square, and

is the area of the larger square.\r
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\n" ); document.write( "\n" ); document.write( "Solve for

for the sides of the sign, subtract 2 for the sides of the poster.\r
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\n" ); document.write( "\n" ); document.write( "John
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\n" ); document.write( "My calculator said it, I believe it, that settles it
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$\"The$

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