document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=372148>Question 372148</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A SQUARE POSTER HAS SIDES MEASURING 2 FEET LESS THAN THE SIDES OF A SQUARE SIGN. IF THE DIFFERENCE BETWEEN THEIR AREAS IS 20 SQUARE FEET, FIND LENGTHS OF THE SIDES OF THE POSTER AND THE SIGN. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #265087 by </B><A HREF=/tutors/aboutme.mpl?userid=Greenfinch><B>Greenfinch(383)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Greenfinch><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Greenfinch><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=265087\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> side of poster is x<BR>\n" );
document.write( "side of sign is x+2<BR>\n" );
document.write( "(x + 2)^2 - x^2 = 20<BR>\n" );
document.write( "x^2 + 4x +4 - x^2 = 20<BR>\n" );
document.write( "4x + 4 = 20<BR>\n" );
document.write( "x = 4<BR>\n" );
document.write( "Check<BR>\n" );
document.write( "poster is 16 sq ft<BR>\n" );
document.write( "sign is 36 sq ft </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );