document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=372132>Question 372132</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the speed of a boat in still water is 15 mph. the boat can travel 60 miles downstream in 2/3 the time it takes to travel 60 miles upstream. what is the rate of the current? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #265083 by </B><A HREF=/tutors/aboutme.mpl?userid=Greenfinch><B>Greenfinch(383)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Greenfinch><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Greenfinch><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=265083\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Downstream time is 60/(15 + c) Upstream time is 60/(15 - c)<BR>\n" );
document.write( "Equation is therefore 3x60/(15 + c) = 2x 60/(15 - c)<BR>\n" );
document.write( "So 180 (15 - c) = 120(15 + c)<BR>\n" );
document.write( "2700 - 180c = 1800 + 120c<BR>\n" );
document.write( "900 = 300c<BR>\n" );
document.write( "c = 3<BR>\n" );
document.write( "Check : Downstream at 18 mph takes 10/3 hours<BR>\n" );
document.write( "Upstream at 12 mph takes 5 or 15/3 hours<BR>\n" );
document.write( "Ratio is 3:2 </SPAN>\n" );
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