document.write( "Question 372126: W and V are a 192 miles apart. A car leaves W traveling towards V and another car leaves V at the same time, traveling towards W. The car leaving W travels 10 miles per hour more than the other and they meet after 1 hour and 36 minutes. What is the average speed of the car? \n" ); document.write( "
Algebra.Com's Answer #265081 by checkley79(3341)\"\" \"About 
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D=RT
\n" ); document.write( "192=(X+X+10)1.6
\n" ); document.write( "192=(2X+10)1.6
\n" ); document.write( "182=3.2X+16
\n" ); document.write( "3.2X=192-16
\n" ); document.write( "3.2X=176
\n" ); document.write( "X=176/3.2
\n" ); document.write( "X=55 MPH FOR THE SLOWER CAR.
\n" ); document.write( "55+10=65 MPH FOR THE FASTER CAR.
\n" ); document.write( "PROOF:
\n" ); document.write( "192=(55+65)1.6
\n" ); document.write( "192=120*1.6
\n" ); document.write( "192=192
\n" ); document.write( "
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