document.write( "Question 372126: W and V are a 192 miles apart. A car leaves W traveling towards V and another car leaves V at the same time, traveling towards W. The car leaving W travels 10 miles per hour more than the other and they meet after 1 hour and 36 minutes. What is the average speed of the car? \n" ); document.write( "
Algebra.Com's Answer #265081 by checkley79(3341)![]() ![]() ![]() You can put this solution on YOUR website! D=RT \n" ); document.write( "192=(X+X+10)1.6 \n" ); document.write( "192=(2X+10)1.6 \n" ); document.write( "182=3.2X+16 \n" ); document.write( "3.2X=192-16 \n" ); document.write( "3.2X=176 \n" ); document.write( "X=176/3.2 \n" ); document.write( "X=55 MPH FOR THE SLOWER CAR. \n" ); document.write( "55+10=65 MPH FOR THE FASTER CAR. \n" ); document.write( "PROOF: \n" ); document.write( "192=(55+65)1.6 \n" ); document.write( "192=120*1.6 \n" ); document.write( "192=192 \n" ); document.write( " \n" ); document.write( " |