document.write( "Question 372093: How much of a 50% solution would have to be added to a 20% solution to make 24 liters of a 30% solution ?
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Algebra.Com's Answer #265058 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi,
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document.write( "Let x represent the total amount of 50% solution. 
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document.write( "Then(24L-x) would be the amount of the 20% solution.
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document.write( ".50x + .20(24L-x) = .30*24L
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document.write( "solving for x
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document.write( ".50x + .20*24L - .20x = .30*24L
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document.write( ".30x = .10*24L
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document.write( "x = 8L of the 50% solution\r
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document.write( "checking our answer
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document.write( "(16L of the 20% solution (24-8)
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document.write( ".50*8 + .20*16 = 4 + 3.2 = 7.2= .30*24 \n" );
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