document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=371974>Question 371974</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The complement of angle x is 9 more than five times the measure of the angle.   Find both angles.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #265042 by </B><A HREF=/tutors/aboutme.mpl?userid=ericareneee><B>ericareneee(4)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ericareneee><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ericareneee><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=265042\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> if the first angle is x, then the complement is 5x+9.<BR>\n" );
document.write( "complement means that both angles added together equals 90<BR>\n" );
document.write( "so the equation is x+5x+9=90\r<BR>\n" );
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document.write( "combine like terms 6x+9=90<BR>\n" );
document.write( "then subtract 9 on both sides 6x=81<BR>\n" );
document.write( "divide 6 x=13.5<BR>\n" );
document.write( "this is the first angle.\r<BR>\n" );
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document.write( "the second angle is 5x+9, so substitute 13.5 for x<BR>\n" );
document.write( "5(13.5)+9=76.5\r<BR>\n" );
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document.write( "check: 13.5+76.5=90\r<BR>\n" );
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document.write( "so the first angle is 13.5 and it's complement is 76.5. </SPAN>\n" );
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