document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=41021>Question 41021</A>: <I><SPAN STYLE=\"word-break: break-all;\"> An infinite geometric series has 1 and 1/5 as its first two terms: 1,1/5,1/25,1/125,..... What is the sum, S, of the infinite series?<BR>\n" );
document.write( "a)1/25<BR>\n" );
document.write( "b)1/4<BR>\n" );
document.write( "c)1<BR>\n" );
document.write( "d)5/4 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #26504 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=26504\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The formula for finding the sum of an infinite geometric series is<BR>\n" );
document.write( "S = a1 / (1 - r)<BR>\n" );
document.write( "where a1 is the first term and r is the common ratio...here those are 1 and 1/5, respectively...plugging in we get<BR>\n" );
document.write( "S = 1 / (1 - 1/5) =<BR>\n" );
document.write( "S = 1 / (4/5) =<BR>\n" );
document.write( "S = 5/4<BR>\n" );
document.write( "Choice D. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );