document.write( "Question 371956: f(x)=-16x^2+8x+3\r
\n" ); document.write( "\n" ); document.write( "The vertex is (1/4,4) and it opens downward.\r
\n" ); document.write( "\n" ); document.write( "I need help determing the x and y intercepts. I have graphed it using the graphing solver but every answer I come up with it wrong. \n" ); document.write( "

Algebra.Com's Answer #264955 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi,
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document.write( "f(x)=-16x^2+8x+3
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document.write( "f(x)=-16[x^2+(1/2)x -3/16}
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document.write( "f(x)=-16[(x-1/4)^2 - 1/16 -3/16}
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document.write( "f(x)=-16(x-1/4)^2 + 4
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document.write( "x intercepts (y=0)
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document.write( "0 = -16(x-1/4)^2 + 4
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document.write( "-4/-16 = (x-1/4)^2  taking the square root of both sides of the equation
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document.write( "+-2/4 = x - 1/4
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document.write( "1/4 +- 1/2 = x
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document.write( "-1/4 = x
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document.write( "3/4 = x
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document.write( "y intercept (x=0)
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document.write( "y = -16(-1/4)^2 + 4
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document.write( "y = -1 + 4 = 3
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