document.write( "Question 371941: Solve the following logarithmic equation. Check all solutions.
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document.write( "log(x)+log(x+21)=2 \n" );
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Algebra.Com's Answer #264954 by CharlesG2(834)![]() ![]() ![]() You can put this solution on YOUR website! Solve the following logarithmic equation. Check all solutions. \n" ); document.write( "log(x)+log(x+21)=2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "log(x) + log(x + 21) = 2 \n" ); document.write( "logarithmic rule: logb(m) + logb(n) = logb(mn) \n" ); document.write( "log(x(x + 21)) = 2 \n" ); document.write( "log when no base is noted is assumed to be base 10 \n" ); document.write( "logarithmic rule: if logb(y) = x then b^x = y \n" ); document.write( "10^2 = x(x + 21) \n" ); document.write( "100 = x^2 + 21x \n" ); document.write( "0 = x^2 + 21x - 100 \n" ); document.write( "0 = (x + 25)(x - 4) \n" ); document.write( "by FOIL this is x^2 - 4x + 25x - 100 or x^2 + 21x - 100 \n" ); document.write( "x = -25 or x = 4 \n" ); document.write( "can not take log of a negative number \n" ); document.write( "10 to the something can not equal -25 \n" ); document.write( "only solution is x = 4 \n" ); document.write( "check: log(4) + log(4 + 21) = 2 = log(4) + log(25) \n" ); document.write( "log(4) + log(25) = log(100) = 2 \n" ); document.write( "10^2 = 100, yes \n" ); document.write( " \n" ); document.write( " |