document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=41072>Question 41072</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the vertex, focus and directix of the graph of the equation:<BR>\n" );
document.write( "12(y+3)=(x-1)^2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #26487 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=26487\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 12(y+3)=(x-1)^2\r<BR>\n" );
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document.write( "This follows the form 4p(y-k)=(x-h)^2<BR>\n" );
document.write( "p=3,k=-3,h=1<BR>\n" );
document.write( "Vertex is at (h,k) = (1,-3)<BR>\n" );
document.write( "The parabola opens up so the focus is 3 above the vertex.<BR>\n" );
document.write( "Focus is at (1,0)<BR>\n" );
document.write( "The directrix is the y-line 3 below the vertex.<BR>\n" );
document.write( "Directrix is y=-6<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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