document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=371779>Question 371779</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A 30% acid solution is to be mixed with a 50% acid solution to get 100 milliliters of a 35% acid solution. How many milliliters of 30% are needed </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #264840 by </B><A HREF=/tutors/aboutme.mpl?userid=amoresroy><B>amoresroy(361)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=amoresroy><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=amoresroy><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=264840\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A 30% acid solution is to be mixed with a 50% acid solution to get 100 milliliters of a 35% acid solution. How many milliliters of 30% are needed\r<BR>\n" );
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document.write( "Let x = the number of milliliters of 30% needed<BR>\n" );
document.write( "100-x = the number of milliliters of 50% needed\r<BR>\n" );
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document.write( "0.30x + 0.50(100-x) = .35(100)<BR>\n" );
document.write( "0.30x + 50 - 0.5x   = 35<BR>\n" );
document.write( "            -0.2x   = 35-50<BR>\n" );
document.write( "                x   = 75<BR>\n" );
document.write( "             <BR>\n" );
document.write( "75 milliliters of 30% are needed\r<BR>\n" );
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document.write( " </SPAN>\n" );
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