document.write( "Question 371640: When the dimensions of a cube are reduced by 4 inches on each side, the surface area of the new cube is 864 square inches. What were the dimensions of the original cube? \n" ); document.write( "
Algebra.Com's Answer #264780 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! When the dimensions of a cube are reduced by 4 inches on each side, \n" ); document.write( " the surface area of the new cube is 864 square inches. \n" ); document.write( " What were the dimensions of the original cube? \n" ); document.write( ": \n" ); document.write( "Let x = length of sides in the original cube \n" ); document.write( ": \n" ); document.write( "Surface area of original cube = 6x^2 \n" ); document.write( ": \n" ); document.write( "New cube surface area: \n" ); document.write( "6(x-4)^2 = 864 \n" ); document.write( ": \n" ); document.write( "FOIL (x-4)(x-4) \n" ); document.write( "6(x^2 - 8x + 16) = 864 \n" ); document.write( ": \n" ); document.write( "Divide both sides by 6 \n" ); document.write( "x^2 - 8x + 16 = 144 \n" ); document.write( ": \n" ); document.write( "A quadratic equation \n" ); document.write( "x^2 - 8x + 16 - 144 = 0 \n" ); document.write( "x^2 - 8x - 128 = 0 \n" ); document.write( ": \n" ); document.write( "Factors to: \n" ); document.write( "(x-16)(x+8) = 0 \n" ); document.write( ": \n" ); document.write( "positive solution: \n" ); document.write( "x = 16 inches, side of original cube \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "New cube side will be 12 inches, find the surface area of new cube: \n" ); document.write( "6(12^2) = 864, confirms our solution \n" ); document.write( " |