document.write( "Question 371607: My homework question states: Write the equation of the linear function whose graph contains the point (-2,4) and is perpendicular to the line whose equation is 2x+y=10. \r
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Algebra.Com's Answer #264708 by mananth(16946)\"\" \"About 
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the given equation is 2x+y=10
\n" ); document.write( "re-write in slope intercept form
\n" ); document.write( "y=-2x+10
\n" ); document.write( "compare with equation
\n" ); document.write( "y = mx+b
\n" ); document.write( "slope m=-2
\n" ); document.write( "..
\n" ); document.write( "the desired line is perpendicular to this line so slope is negative reciprocal of the given line
\n" ); document.write( "slope = 1/2
\n" ); document.write( "..
\n" ); document.write( "passing through (-2,4)
\n" ); document.write( "y= mx+b
\n" ); document.write( "plug value of m x,y
\n" ); document.write( "4=1/2*-2+b
\n" ); document.write( "4=-1+b
\n" ); document.write( "b=5
\n" ); document.write( "so the line will be y = (1/2)x+5
\n" ); document.write( "\"graph%28300%2C300%2C-6%2C6%2C-1%2C10%2C%28-2x%2B10%29%2C%28%28x%2F2%29%2B5%29%29%29\"
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\n" ); document.write( "m.ananth@hotmail.ca
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