document.write( "Question 371596: This is a practice question that I have and I am completely stuck...\r
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document.write( "A certain sum of money is invested at 10%. Twice that amount is invested at 8%. The total amount of interest from both investments is $91. How much is invested at 8%.\r
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document.write( "Here is all that I have \r
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document.write( "91 = (x)(.1)(1) + (y)(.08)(2)
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document.write( "910 = x + .16y\r
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document.write( "I am not sure where to go from here and to be honest, I am not even sure if I am on the right track... Please Help ... Thank You
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Algebra.Com's Answer #264707 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! .10x+.08*2x=91 \n" ); document.write( ".10x+.16x=91 \n" ); document.write( ".26x=91 \n" ); document.write( "x=91/.26 \n" ); document.write( "x=350 invested @ 10%. \n" ); document.write( "2*350=700 invested @ 8% \n" ); document.write( "Proof: \n" ); document.write( ".10*350+.08*700=91 \n" ); document.write( "35+56=91 \n" ); document.write( "91=91 \n" ); document.write( " |