document.write( "Question 371607: My homework question states: Write the equation of the linear function whose graph contains the point (-2,4) and is perpendicular to the line whose equation is 2x+y=10. \r
\n" ); document.write( "\n" ); document.write( "How do I solve this?
\n" ); document.write( "

Algebra.Com's Answer #264699 by checkley77(12844)\"\" \"About 
You can put this solution on YOUR website!
(-2,4) and is perpendicular to the line whose equation is
\n" ); document.write( "2x+y=10 ( red line).
\n" ); document.write( "Y=-2X+10 THIS LINE HAS A SLOPE=-2
\n" ); document.write( "THEREFORE A PERPENDICULAR LINE WILL HAVE A SLOPE=+1/2 (THE NEGATIVE RECIPRICAL)
\n" ); document.write( "Y=mX+b where m=slope & b=the y intercept.
\n" ); document.write( "Substitute the values of the X & Y points & solve for b.
\n" ); document.write( "4=1/2*-2+b
\n" ); document.write( "4=-1+b
\n" ); document.write( "b=4+1
\n" ); document.write( "b=5 Thus the equation is:
\n" ); document.write( "Y=X/2+5 (green line)
\n" ); document.write( " \"+graph%28+300%2C+300%2C+-10%2C+10%2C+-10%2C+10%2C+-2x+%2B10%2C+x%2F2+%2B5%29+\" (graph 300x300 pixels, x from -10 to 10, y from -10 to 10, of TWO functions -2x +10 and x/2 +5).
\n" ); document.write( "
\n" );