document.write( "Question 371397: How can I solve this equation and find the solutions if the solution set is greater than or equal to 0 and less than 2pi.\r
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document.write( "--> {{tan^2*theta= (3/2)secant*theta}} \n" );
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Algebra.Com's Answer #264588 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! tan^2(t) = (3/2)sec(t) \n" ); document.write( "sin^2/cos^2 = (3/2)/cos \n" ); document.write( "Multiply thru by cos^2 \n" ); document.write( "sin^2 = (3/2)cos \n" ); document.write( "1 - cos^2 = (3/2)cos \n" ); document.write( "2 - 2cos^2 = 3 cos \n" ); document.write( "2cos^2 + 3cos - 2 = 0 \n" ); document.write( "Sub x for cos \n" ); document.write( "(2x - 1)*(x + 2) = 0 \n" ); document.write( "x= 1/2 \n" ); document.write( "cos(t) = 1/2 \n" ); document.write( "theta = 60º, 300º \n" ); document.write( "------------- \n" ); document.write( "x = -2 \n" ); document.write( "cos(theta) = -2 Not a real number, ignore \n" ); document.write( " \n" ); document.write( " |