document.write( "Question 371376: solution A 30% acid, solution B is 100% acid. How many liters should be combined to make 28 liters of a solution that is 50%acid?\r
\n" ); document.write( "\n" ); document.write( "X + Y = 28
\n" ); document.write( "30% 100%=50%
\n" ); document.write( "30x 100y 50% of 24 liters <\n" ); document.write( "\n" ); document.write( "
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Algebra.Com's Answer #264584 by Alan3354(69443)\"\" \"About 
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solution A 30% acid, solution B is 100% acid. How many liters should be combined to make 28 liters of a solution that is 50%acid?\r
\n" ); document.write( "\n" ); document.write( "X + Y = 28
\n" ); document.write( "30% 100%=50%
\n" ); document.write( "30x 100y 50% of 24 liters <\n" ); document.write( "------------------
\n" ); document.write( "x = amount of solution A
\n" ); document.write( "y = amount of B
\n" ); document.write( "---------------
\n" ); document.write( "x + y = 28 --> y = 28-x
\n" ); document.write( "0.3x + y = 0.5*28 = 14
\n" ); document.write( "--------------
\n" ); document.write( "y = 28-x
\n" ); document.write( "0.3x + 28-x = 14
\n" ); document.write( "-0.7x = -14
\n" ); document.write( "x = 20 liters
\n" ); document.write( "y = 8 liters
\n" ); document.write( "-----------------
\n" ); document.write( "I would have used A and B instead of x and y, but the answer is the same.\r
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