document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=371361>Question 371361</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two angles are complementary. One angle's measure is teen degrees less the three times the measure of the other. Find the measure of each of the angles using the method we used in class for word problems showing each step. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #264582 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=264582\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Two angles are complementary. One angle's measure is teen degrees less the three times the measure of the other. Find the measure of each of the angles using the method we used in class for word problems showing each step.<BR>\n" );
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document.write( "I wasn't in class that day.<BR>\n" );
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document.write( "Angles are x and y<BR>\n" );
document.write( "x + y = 90 degrees<BR>\n" );
document.write( "x = 3y - 10<BR>\n" );
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document.write( "(3y-10) + y = 90<BR>\n" );
document.write( "4y - 10 = 90<BR>\n" );
document.write( "4y = 100<BR>\n" );
document.write( "y = 25 degs<BR>\n" );
document.write( "x = 65 degs<BR>\n" );
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